Question 104
Let $ABCD$ be a parallelogram, and let $P$ be a point on the side $AB$. Let the line through $P$ parallel to $BC$ intersect the diagonal $AC$ at point $Q$. Prove that
$$|DAQ|^{2} = |PAQ| \times |BCD|,$$
where $|XYZ|$ denotes the area of triangle $XYZ$.
$$|DAQ|^{2} = |PAQ| \times |BCD|,$$
where $|XYZ|$ denotes the area of triangle $XYZ$.