Question 91
The sequence $(a_{n})$ is defined by $a_{1}=1$ and
$$
a_{n} = \frac{1}{n} + \frac{1}{a_{1} \cdot \ldots \cdot a_{n-1}}
$$
Show that for every integer $m \geqslant 3$, we have $a_{m} \leqslant 1$.
$$
a_{n} = \frac{1}{n} + \frac{1}{a_{1} \cdot \ldots \cdot a_{n-1}}
$$
Show that for every integer $m \geqslant 3$, we have $a_{m} \leqslant 1$.