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MathNet 2025-part-01 — 187 problems (EN–VI) Question 160

Math Olympiad Vault · MathNet 2025-part-01 — 187 problems (EN–VI)

Question 160

For a five-digit number $n = abcde$ we define the twisted sum of $n$ as the value
$$bcdea + cdeab + deabc + eabcd.$$
For example, the twisted sum of $20253$ is
$$05232 + 25320 + 53202 + 32025 = 113079.$$
Let $m$ and $n$ be two five-digit numbers with the same twisted sum. Prove that $m = n$.