Question 24In $\triangle ABC$ we have $AB = 7,$ $AC = 8,$ and $BC = 9.$ Point $D$ is on the circumscribed circle of the triangle so that $\overline{AD}$ bisects $\angle BAC.$ What is the value of $\frac{AD}{CD}?$$\dfrac{9}{8}$$\dfrac{5}{3}$$2$$\dfrac{17}{7}$$\dfrac{5}{2}$