Question 20
Let $a, b, c$ be nonnegative numbers such that $a \ge b \ge c$. Prove that
$$
a^3 + b^3 + c^3 - 3abc \ge \frac{9}{2}(a-b)(b^2-c^2).
$$
$$
a^3 + b^3 + c^3 - 3abc \ge \frac{9}{2}(a-b)(b^2-c^2).
$$
Math Olympiad Vault · MathNet 2025 — 50 problems — Part 01