Question 107
Show that the only choice of integers $x, y, z$ that satisfies the equation
$$
x^{2022} + 20y^{2022} = 22z^{2022},
$$
is $x = y = z = 0$.
$$
x^{2022} + 20y^{2022} = 22z^{2022},
$$
is $x = y = z = 0$.
MathNet 2026 — Part 06 Question 107
Math Olympiad Vault · MathNet 2026 — Part 06