Question 64
Let $a$, $b$, $c \geq 0$ be real numbers with $a + b + c = 1$. Show that
$$
a + b + c \leq \sqrt{a(1+b)} + \sqrt{b(1+c)} + \sqrt{c(1+a)} \leq 2.
$$
$$
a + b + c \leq \sqrt{a(1+b)} + \sqrt{b(1+c)} + \sqrt{c(1+a)} \leq 2.
$$
Math Olympiad Vault · MathNet 2026 — Part 06