Question 39
Let $ABC$ be a triangle with sides of lengths $a$, $b$ and $c$. Let the bisector of the angle $C$ cut $AB$ in $D$. Prove that the length of $CD$ is
$$
\frac{2ab \cos \frac{C}{2}}{a+b}
$$
$$
\frac{2ab \cos \frac{C}{2}}{a+b}
$$
Math Olympiad Vault · MathNet 2026 — Part 03