Question 116
be $a$ e $b$ positive integers such that $a \gt b$. Professor Fernando told student Raul that if he calculated the number $A = a^{2} + 4b + 1$, the result would be a perfect square. Raul, by mistake, exchanged the numbers $a$ e $b$ and calculated the number $B = b^{2} + 4a + 1$ Which, by chance, is also a perfect square.
a) show that $A = (a+1)^{2}$.
b) find the numbers $a$, $b$, $A$ e $B$.
a) show that $A = (a+1)^{2}$.
b) find the numbers $a$, $b$, $A$ e $B$.