Question 86
Let $ABC$ be a triangle, with $AB \le BC$. Let $M$ be the midpoint of the side $BC$, $N$ be the foot of the angle bisector of $\angle B$, $O$ the meeting point of the straight lines $AM$ and $AB$, and $P$ the meeting point of the straight lines $CO$ and $AB$. Show that $4AP \le AB + BC$.