Question 76
For nonnegative real numbers $a,b$, prove that
$$\left(\frac{a+b}{2}\right)^9\ge a^3b^3\left(\frac{a^3+b^3}{2}\right).$$
$$\left(\frac{a+b}{2}\right)^9\ge a^3b^3\left(\frac{a^3+b^3}{2}\right).$$
MathNet 2010 — Part 04 Question 76
Math Olympiad Vault · MathNet 2010 — Part 04