Question 1
Experiment 1
Measuring the Vitamin C Content in Various Samples
Vitamin C is an essential nutrient for humans and certain animal species. Vitamin C refers to the number of vitamers that contain vitamin C activity in animals, including ascorbic acid and its salts, and some oxidized forms of the molecule like dehydroascorbic acid. Ascorbate and ascorbic acid are both naturally present in the body when either of these is introduced into the cells, since the forms interconvert according to the pH. Vitamin C is a water soluble vitamin, and is essential for growth and development. Fruits and vegetables contain vitamin C, and some have more than others. Since iodine reacts quickly with vitamin C, a color change will be seen after the iodine has oxidized the entire vitamin C content. A color change is noted by a final reaction with starch. The number of drops can, then, be calculated into an estimated concentration of the amount of vitamin C.
Objectives
1\. To measure the amount of vitamin C and the pH level in various samples of orange.
2\. To find the correlation between the amount of vitamin C and the pH level.
You will need
1\. Ascorbic acid solution as the basic standard (Plastic test jar A)
2\. Commercial orange juice (Plastic test jar B)
3\. Lemon water (Plastic test jar C)
4\. Half fresh orange inside plastic test jar D,
5\. Starch solution (Plastic test jar E)
6\. Iodine (Plastic test jar F)
7\. Plastic test jar G
8\. 4 glass test tubes, with the following label; A, B, C, D. The test tubes have already
9\. marked for volumes equal to 4 ml.
10\. Pipettes
11\. 4 pH indicator sticks
12\. pH color standard
What to do
1\. Using the pH indicator stick, measure the pH level of samples in plastic test jar A, B, and C, by dipping it into the liquid sample and observing the color that appears. For an indicator, you can only see where its range is based on pH color standard. Write down the results into the table on the answer sheet.
2\. Add to the plastic test jar G, 10 drops of the starch solution from plastic test jar E by pipette. Then, using the other pipette, add iodine drop by drop, and shake gently until the color changes to the shade of blue-black. Set this plastic jar aside as a positive control for later comparison.
3\. Pour the Ascorbic acid solution (in plastic test jar A) to the mark indicated in Test Tube A. Add 20 drops of the starch solution. Using the other pipette, then, add iodine drop by drop and shake gently until the color changes to the shade of blue-black. Note the number of drops when the color changes (You will use the data as the standard)
4\. Pour the commercial orange juice to the mark indicated in Test Tube B. Add 20 drops of the starch solution. Then, using the other pipette, add the iodine drop by drop, and shake gently until the color changes to blue-black. Note the number of drops when the color changes.
5\. Repeat of step 4 for Test Tube C (lemon water).
6\. To get the orange juice from the fresh oranges, squeeze the fruit and the juice out of the oranges into the plastic test jar D.
7\. Using the pH indicator stick, measure the pH level of samples in plastic test jar D with the same procedure as step 1.
8\. Pick out the seeds, before pour into the Test Tube D. Repeat of step 4 for Test Tube D (fresh orange juice).
9\. Calculate the vitamin C concentrations in all of the solutions using the following formula:
$$\frac{\substack{\text{Number of iodine drops}\\\text{in the sample solutions}}}{\substack{\text{Number of iodine drops}\\\text{in ascorbic acid solution}}}=\substack{\text{The concentration in}\\\text{milligram per milliliter (mg/ml)}}$$
Use this as an example: It took 44 drops of iodine solution to change the color of vitamin C solution. It took 12 rops of iodine solution to change the color of the juice. Vitamin C in the juice = 12/44, Vitamin C in the juice = 0,272 mg/ml
10\. Write down the vitamin C concentration into the table on the answer sheet (8 points)
Questions:
1\. Which sample has the highest pH level? Explain your answer! (1.5 points)
2\. Which sample contains the lowest concentration of vitamin C? Explain your answer! (1.5 points)
3\. Based on your experiment results, explain the correlation between vitamin C and pH level of your sample solutions! (2 points)
4\. Vitamin C should be consumed every day. The average dose required for adults is 60-90 mg/day. How many milliliters of commercial orange juice (Test Tube B) must be consumed by adults, according to your data? (3points)
5\. Draw the diagram showing the correlation between the pH level and vitamin C concentration! (4 points)
Answer-sheet table (blank in the supplied key):
| Solutions | pH level | Number of Iodine Drops | Vitamin C Concentrations (mg/ml) |
| --- | --- | --- | --- |
| Ascorbic acid | | | |
| Commercial orange juice | | | |
| Lemon water | | | |
| Fresh orange juice | | | |
Measuring the Vitamin C Content in Various Samples
Vitamin C is an essential nutrient for humans and certain animal species. Vitamin C refers to the number of vitamers that contain vitamin C activity in animals, including ascorbic acid and its salts, and some oxidized forms of the molecule like dehydroascorbic acid. Ascorbate and ascorbic acid are both naturally present in the body when either of these is introduced into the cells, since the forms interconvert according to the pH. Vitamin C is a water soluble vitamin, and is essential for growth and development. Fruits and vegetables contain vitamin C, and some have more than others. Since iodine reacts quickly with vitamin C, a color change will be seen after the iodine has oxidized the entire vitamin C content. A color change is noted by a final reaction with starch. The number of drops can, then, be calculated into an estimated concentration of the amount of vitamin C.
Objectives
1\. To measure the amount of vitamin C and the pH level in various samples of orange.
2\. To find the correlation between the amount of vitamin C and the pH level.
You will need
1\. Ascorbic acid solution as the basic standard (Plastic test jar A)
2\. Commercial orange juice (Plastic test jar B)
3\. Lemon water (Plastic test jar C)
4\. Half fresh orange inside plastic test jar D,
5\. Starch solution (Plastic test jar E)
6\. Iodine (Plastic test jar F)
7\. Plastic test jar G
8\. 4 glass test tubes, with the following label; A, B, C, D. The test tubes have already
9\. marked for volumes equal to 4 ml.
10\. Pipettes
11\. 4 pH indicator sticks
12\. pH color standard
What to do
1\. Using the pH indicator stick, measure the pH level of samples in plastic test jar A, B, and C, by dipping it into the liquid sample and observing the color that appears. For an indicator, you can only see where its range is based on pH color standard. Write down the results into the table on the answer sheet.
2\. Add to the plastic test jar G, 10 drops of the starch solution from plastic test jar E by pipette. Then, using the other pipette, add iodine drop by drop, and shake gently until the color changes to the shade of blue-black. Set this plastic jar aside as a positive control for later comparison.
3\. Pour the Ascorbic acid solution (in plastic test jar A) to the mark indicated in Test Tube A. Add 20 drops of the starch solution. Using the other pipette, then, add iodine drop by drop and shake gently until the color changes to the shade of blue-black. Note the number of drops when the color changes (You will use the data as the standard)
4\. Pour the commercial orange juice to the mark indicated in Test Tube B. Add 20 drops of the starch solution. Then, using the other pipette, add the iodine drop by drop, and shake gently until the color changes to blue-black. Note the number of drops when the color changes.
5\. Repeat of step 4 for Test Tube C (lemon water).
6\. To get the orange juice from the fresh oranges, squeeze the fruit and the juice out of the oranges into the plastic test jar D.
7\. Using the pH indicator stick, measure the pH level of samples in plastic test jar D with the same procedure as step 1.
8\. Pick out the seeds, before pour into the Test Tube D. Repeat of step 4 for Test Tube D (fresh orange juice).
9\. Calculate the vitamin C concentrations in all of the solutions using the following formula:
$$\frac{\substack{\text{Number of iodine drops}\\\text{in the sample solutions}}}{\substack{\text{Number of iodine drops}\\\text{in ascorbic acid solution}}}=\substack{\text{The concentration in}\\\text{milligram per milliliter (mg/ml)}}$$
Use this as an example: It took 44 drops of iodine solution to change the color of vitamin C solution. It took 12 rops of iodine solution to change the color of the juice. Vitamin C in the juice = 12/44, Vitamin C in the juice = 0,272 mg/ml
10\. Write down the vitamin C concentration into the table on the answer sheet (8 points)
Questions:
1\. Which sample has the highest pH level? Explain your answer! (1.5 points)
2\. Which sample contains the lowest concentration of vitamin C? Explain your answer! (1.5 points)
3\. Based on your experiment results, explain the correlation between vitamin C and pH level of your sample solutions! (2 points)
4\. Vitamin C should be consumed every day. The average dose required for adults is 60-90 mg/day. How many milliliters of commercial orange juice (Test Tube B) must be consumed by adults, according to your data? (3points)
5\. Draw the diagram showing the correlation between the pH level and vitamin C concentration! (4 points)
Answer-sheet table (blank in the supplied key):
| Solutions | pH level | Number of Iodine Drops | Vitamin C Concentrations (mg/ml) |
| --- | --- | --- | --- |
| Ascorbic acid | | | |
| Commercial orange juice | | | |
| Lemon water | | | |
| Fresh orange juice | | | |














