Circle $\mathrm{I}$ is circumscribed about a given square and circle $\mathrm{II}$ is inscribed in the given square. If $r$ is the ratio of the area of circle $\mathrm{I}$ to that of circle $\mathrm{II},$ then $r$ equals:
$AB$ is a diameter of a circle centered at $O.$ $C$ is a point on the circle such that angle $BOC$ is $60^\circ.$ If the diameter of the circle is $5$ inches, the length of chord $AC,$ expressed in inches, is:
The length of the common chord of two intersecting circles is $16$ feet. If the radii are $10$ feet and $17$ feet, a possible value for the distance between the centers of the circles, expressed in feet, is:
The sides of triangle $BAC$ are in the ratio $2:3:4.$ $BD$ is the angle-bisector drawn to the shortest side $AC,$ dividing it into segments $AD$ and $CD.$ If the length of $AC$ is $10,$ then the length of the longer segment of $AC$ is:
The length of rectangle $ABCD$ is $5$ inches and its width is $3$ inches. Diagonal $AC$ is divided into three equal segments by points $E$ and $F.$ The area of triangle $BEF,$ expressed in square inches, is:
Let $s_1$ be the sum of the first $n$ terms of the arithmetic sequence $8,$ $12,$ $\ldots$ and let $s_2$ be the sum of the first $n$ terms of the arithmetic sequence $17,$ $19,$ $\ldots.$ Then $s_1=s_2$ for: