Question 3
Let $ABCD$ be a rectangle with $BC = 3 AB$. Show that if $P, Q$ are the points on side $BC$ with $BP = PQ = QC$, then
$$
\angle DBC + \angle DPC = \angle DQC.
$$
$$
\angle DBC + \angle DPC = \angle DQC.
$$
Math Olympiad Vault · MathNet 1974 — Part 01