Question 64
Find all four digit numbers $A$ such that
$$
\frac{1}{3} A+2000=\frac{2}{3} \bar{A}
$$
where $\bar{A}$ is the number with the same digits as $A$, but written in opposite order. (For example, $\overline{1234}=4321$.)
$$
\frac{1}{3} A+2000=\frac{2}{3} \bar{A}
$$
where $\bar{A}$ is the number with the same digits as $A$, but written in opposite order. (For example, $\overline{1234}=4321$.)