Question 128Suppose $x, y \in (-2, 2)$ and $xy = -1$. Then the minimum value of $u = \frac{4}{4-x^2} + \frac{9}{9-y^2}$ is ( ).$\frac{8}{5}$$\frac{24}{11}$$\frac{12}{7}$$\frac{12}{5}$