Question 72
A circle through the vertex $A$ of $\triangle ABC$, $AB \neq AC$, meets the sides $AB$ and $AC$ at points $M$ and $N$, respectively, and the side $BC$ at points $P$ and $Q$, where $Q$ lies between $B$ and $P$. Find $\measuredangle BAC$, if $MP \parallel AC$, $NQ \parallel AB$ and $\frac{BP}{CQ}=\frac{AB}{AC}$.