Question 67
Proportional numbers. If $\frac{x}{y}=\frac{3}{z}$, then $9 y^{2}$ equals:
(a) $\frac{x^{2}}{9}$
(b) $x^{3} z$
(c) $3 x^{2}$
(d) $x^{2} z^{2}$
(e) $\frac{1}{9} x^{2} z^{2}$
(a) $\frac{x^{2}}{9}$
(b) $x^{3} z$
(c) $3 x^{2}$
(d) $x^{2} z^{2}$
(e) $\frac{1}{9} x^{2} z^{2}$