Question 176
Prove that there is no real number $x$ for which
$$
\frac{1}{9}\lt\frac{\tan 3 x}{\tan 2 x} \leq \frac{3}{2}
$$
holds.
$$
\frac{1}{9}\lt\frac{\tan 3 x}{\tan 2 x} \leq \frac{3}{2}
$$
holds.
Math Olympiad Vault · MathNet 2007-part-02 — 187 problems (EN–VI)