Question 158
Given is a (general) trapezoid $ABCD$ whose diagonals meet at the point $P$. A point $Q$ lies between the parallels $AB$ and $DC$ such that $\angle AQB = \angle CQD$ holds and the line $BC$ runs between $P$ and $Q$.
Prove that $\angle DQP = \angle BAQ$ holds.
Prove that $\angle DQP = \angle BAQ$ holds.