Question 112
The number of rational solutions to the system of equations
$$
\begin{cases} x + y + z = 0, \\ xyz + z = 0, \\ xy + yz + xz + y = 0 \end{cases}, \text{ is } (\quad).
$$
$$
\begin{cases} x + y + z = 0, \\ xyz + z = 0, \\ xy + yz + xz + y = 0 \end{cases}, \text{ is } (\quad).
$$