Question 163
Solve the system:
$$
\begin{cases}
x(y+z) = 35 \\
y(z+x) = 32 \\
z(x+y) = 27
\end{cases}
$$
$$
\begin{cases}
x(y+z) = 35 \\
y(z+x) = 32 \\
z(x+y) = 27
\end{cases}
$$
MathNet 2008-part-02 — 165 problems (EN–VI) Question 163
Math Olympiad Vault · MathNet 2008-part-02 — 165 problems (EN–VI)