Question 122
Solve the equation
$$
12^{x} + y^{4} = 2008^{z}
$$
in the set of integers.
$$
12^{x} + y^{4} = 2008^{z}
$$
in the set of integers.
MathNet 2008-part-03 — 165 problems (EN–VI) Question 122
Math Olympiad Vault · MathNet 2008-part-03 — 165 problems (EN–VI)