Question 73
Prove that there is an angle $x$ such that
$$
\sin x = \frac{\sin \beta \cdot \sin \gamma}{1 - \cos \alpha \cdot \cos \beta \cdot \cos \gamma},
$$
for every angle $\alpha$, and $\beta$ and $\gamma$ acute angles.
$$
\sin x = \frac{\sin \beta \cdot \sin \gamma}{1 - \cos \alpha \cdot \cos \beta \cdot \cos \gamma},
$$
for every angle $\alpha$, and $\beta$ and $\gamma$ acute angles.