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MathNet 2008-part-04 — 165 problems (EN–VI) Question 147

Math Olympiad Vault · MathNet 2008-part-04 — 165 problems (EN–VI)

Question 147

In acute triangle $ABC$, the three altitudes meet at $H$. Given that $AH = BC$, calculate at least one of the angles of $\triangle ABC$.

Answer: $\angle A = 45^{\circ}$ (angles $B$ and $C$ cannot be determined).