Question 162
Solve the equation
$$
(x^2 - x + 1)(4y^2 + 6y + 4)(4z^2 - 12z + 25) = 21
$$
in the set of real numbers.
$$
(x^2 - x + 1)(4y^2 + 6y + 4)(4z^2 - 12z + 25) = 21
$$
in the set of real numbers.
MathNet 2009-part-02 — 175 problems (EN–VI) Question 162
Math Olympiad Vault · MathNet 2009-part-02 — 175 problems (EN–VI)