Question 53
Let $P$ be an interior point of a triangle $ABC$. Show, with usual notations, that
$$
\frac{PA}{a} + \frac{PB}{b} + \frac{PC}{c} \ge \sqrt{3}.
$$
$$
\frac{PA}{a} + \frac{PB}{b} + \frac{PC}{c} \ge \sqrt{3}.
$$
Math Olympiad Vault · MathNet 2009-part-02 — 175 problems (EN–VI)