Question 24
Prove that $1005^{\ln 121} = 11^{\ln(1+3+5+\dots+2009)}$.
MathNet 2009-part-04 — 175 problems (EN–VI) Question 24
Math Olympiad Vault · MathNet 2009-part-04 — 175 problems (EN–VI)
Math Olympiad Vault · MathNet 2009-part-04 — 175 problems (EN–VI)