Question 8Given that the area of $\triangle ABC$ is 1 and $\frac{BD}{CD}=\frac{CE}{EF}=\frac{AF}{FD}=\frac12$, what is the area of $\triangle DEF$? $\frac7{75}$$\frac8{75}$$\frac8{27}$$\frac13$$\frac9{21}$