Question 35
Real numbers $x, y$ satisfy the inequality:
$$
x^2 + 3xy + 4y^2 \leq \frac{7}{2}.
$$
Prove that $x + y \leq 2$.
$$
x^2 + 3xy + 4y^2 \leq \frac{7}{2}.
$$
Prove that $x + y \leq 2$.
MathNet 2011 Question 35
Math Olympiad Vault · MathNet 2011