Question 23
Determine the set of all real numbers $x$ that satisfy the equation
$$
\left\lfloor \frac{2x-1}{3} \right\rfloor + \left\lfloor \frac{4x+1}{6} \right\rfloor = \frac{5x-4}{3},
$$
where $\lfloor a \rfloor$ denotes the largest integer not greater than $a$.
$$
\left\lfloor \frac{2x-1}{3} \right\rfloor + \left\lfloor \frac{4x+1}{6} \right\rfloor = \frac{5x-4}{3},
$$
where $\lfloor a \rfloor$ denotes the largest integer not greater than $a$.