Question 61
Given that
$$
\frac{1 + 3 + 5 + \cdots + (2n - 1)}{2 + 4 + 6 + \cdots + (2n)} = \frac{2011}{2012},
$$
determine $n$.
$$
\frac{1 + 3 + 5 + \cdots + (2n - 1)}{2 + 4 + 6 + \cdots + (2n)} = \frac{2011}{2012},
$$
determine $n$.
Math Olympiad Vault · MathNet 2012