Question 27
Show that
$$
\sum_{n=0}^{1006} \frac{2012!}{(n!(1006-n)!)^2}
$$
is a perfect square.
$$
\sum_{n=0}^{1006} \frac{2012!}{(n!(1006-n)!)^2}
$$
is a perfect square.
MathNet 2012 Question 27
Math Olympiad Vault · MathNet 2012
Math Olympiad Vault · MathNet 2012