Question 2
Find all pairs $(x, y)$ of positive integers such that
$$
\frac{1}{x^2} + \frac{249}{xy} + \frac{1}{y^2} = \frac{1}{2012}.
$$
$$
\frac{1}{x^2} + \frac{249}{xy} + \frac{1}{y^2} = \frac{1}{2012}.
$$
MathNet 2012 Question 2
Math Olympiad Vault · MathNet 2012