Question 100
For real numbers $a,b$ with $|a|\ne|b|$ and $a\ne0$,
$$
\frac{a-b}{a^2+ab}+\frac{a+b}{a^2-ab}=\frac{3a-b}{a^2-b^2}.
$$
Determine the value of $\frac ba$.
$$
\frac{a-b}{a^2+ab}+\frac{a+b}{a^2-ab}=\frac{3a-b}{a^2-b^2}.
$$
Determine the value of $\frac ba$.