Question 65
For real numbers $a$ and $b$, such that $|a| \neq |b|$ and $a \neq 0$, we have
$$
\frac{a-b}{a^2+ab} + \frac{a+b}{a^2-ab} = \frac{3a-b}{a^2-b^2}.
$$
Determine the value of the expression $\frac{b}{a}$.
$$
\frac{a-b}{a^2+ab} + \frac{a+b}{a^2-ab} = \frac{3a-b}{a^2-b^2}.
$$
Determine the value of the expression $\frac{b}{a}$.