Question 52
Determine all the pairs of real numbers $(x, y)$, which are solutions of the system:
$$
\begin{cases}
(x^2 + y^2)^2 - xy(x+y)^2 = 19 \\
|x-y| = 1
\end{cases}
$$
$$
\begin{cases}
(x^2 + y^2)^2 - xy(x+y)^2 = 19 \\
|x-y| = 1
\end{cases}
$$
Math Olympiad Vault · MathNet 2014