Question 42
Let $\Omega$ be the circumcircle of a triangle $ABC$. A circle passing through the vertex $A$ and touching $BC$ at point $X$ meets $\Omega$ at point $Y$ (different from $A$). Let point $Z$ (different from $Y$) be the intersection point of the ray $YX$ and $\Omega$.
$$
\angle CAX = \angle ZAB.
$$
$$
\angle CAX = \angle ZAB.
$$