Question 81
Let $x$ be the number of trailing zeros of $2000!$ in base 5 and $y$ the number of trailing zeros of $2013!$ in base 10. Find $x-y$. (For a positive integer $n$, $n!$ is the product of all positive integers at most $n$.)
(A)$-2$
(B)$0$
(C)$2013$
(D)$13!$
(E)None of the above.
(A)$-2$
(B)$0$
(C)$2013$
(D)$13!$
(E)None of the above.