Question 5
Diagonal $BD$ divides parallelogram $ABCD$ into two equal triangles. A regular hexagon in $ABD$ has two consecutive sides on $AB,AD$ and one vertex on $BD$. Another regular hexagon in $BCD$ has two consecutive vertices on $BC,CD$ and one side on $BD$. Which hexagon has larger area? (9 points)
The official original explicitly gives $\angle A=120^\circ$; the supplied Vietnamese statement omits this angle. It is also implied by the two consecutive sides of the regular hexagon lying along $AB,AD$ at $A$.
The official original explicitly gives $\angle A=120^\circ$; the supplied Vietnamese statement omits this angle. It is also implied by the two consecutive sides of the regular hexagon lying along $AB,AD$ at $A$.