Question 22
The three fractions are equal: $\frac{3}{A}=\frac{B}{12}=\frac{4}{C}$. Find the difference between the largest and smallest possible values of $A+B+C$.
Practice clarification: take $A,B,C$ to be positive natural numbers. This condition is used in the intended solution but is omitted from the original question.
Practice clarification: take $A,B,C$ to be positive natural numbers. This condition is used in the intended solution but is omitted from the original question.