Question 5
Real numbers $a,b$ satisfy
$$\begin{cases}6-5a+4b-3a^2+2ab-b^2=0,\\a-b=1.\end{cases}$$
Find the sum of all possible values of $30a/b$.
$$\begin{cases}6-5a+4b-3a^2+2ab-b^2=0,\\a-b=1.\end{cases}$$
Find the sum of all possible values of $30a/b$.