Question 2
Find the least possible value of
$$f(x)=\frac8{1+\cos x}+\frac{18}{1-\cos x},$$
where $x$ is any real number for which $f(x)$ is defined.
$$f(x)=\frac8{1+\cos x}+\frac{18}{1-\cos x},$$
where $x$ is any real number for which $f(x)$ is defined.