Question 2
In the figure, $AD$ bisects $\angle BAC$ and $\angle CDA=45^\circ$. Find $\angle BED$. The right-angle mark means $CE\perp AB$; $B,D,C$ are collinear and $B,E,A$ are collinear. $F$ is the intersection of $AD$ and $CE$.


SEAMO · SEAMO 2027 - Paper E - SET 01 - Self-study
