Question 15
In triangle $ABC$, point $D$ lies on segment $AC$ such that $AB=AD$ and $\angle ABC-\angle ACB=30^\circ$. Find $\angle CAD$.
The target is retained exactly as printed: angle CAD, not another angle in the figure. Answer that literal question; a discrepancy with the source key is discussed in the solution.
The target is retained exactly as printed: angle CAD, not another angle in the figure. Answer that literal question; a discrepancy with the source key is discussed in the solution.