Question 17Triangle $ABC$ has area 1. In the arrangement shown, $\frac{BD}{CD}=\frac{CE}{EF}=\frac{AF}{FD}=\frac12$. Find the area of triangle $DEF$. $\frac7{75}$$\frac8{75}$$\frac8{27}$$\frac13$$\frac9{21}$