Question 6
Find all positive integer solutions of the equation
$$
(x^2 - 1)^2 (y^2 - 1)^2 + 16x^2 y^2 = z^2.
$$
$$
(x^2 - 1)^2 (y^2 - 1)^2 + 16x^2 y^2 = z^2.
$$
MathNet 2015-part-04 — 191 problems (EN–VI) Question 6
Math Olympiad Vault · MathNet 2015-part-04 — 191 problems (EN–VI)