Question 177
Solve the system of equations
$$
\begin{cases} 6x - y + z^2 = 3 \\ x^2 - y^2 - 2z = -1 \\ 6x^2 - 3y^2 - z - 2z^2 = 0 \end{cases} \quad (x, y, z \in \mathbb{R})
$$
$$
\begin{cases} 6x - y + z^2 = 3 \\ x^2 - y^2 - 2z = -1 \\ 6x^2 - 3y^2 - z - 2z^2 = 0 \end{cases} \quad (x, y, z \in \mathbb{R})
$$