Question 14
Find at least one pair of positive integers $(x, y)$, which satisfies an equality:
$$
\frac{1}{2}(x^2 - y^3) = 2016.
$$
$$
\frac{1}{2}(x^2 - y^3) = 2016.
$$
MathNet 2016-part-07 — 182 problems (EN–VI) Question 14
Math Olympiad Vault · MathNet 2016-part-07 — 182 problems (EN–VI)