Question 49
Find the smallest integer solution of the equation
$$
\left\lfloor \frac{x}{8} \right\rfloor - \left\lfloor \frac{x}{40} \right\rfloor + \left\lfloor \frac{x}{240} \right\rfloor = 210.
$$
(If $x$ is a real number, $\lfloor x \rfloor$ is the integer part of $x$, that is, the greatest integer less than or equal to $x$.)
$$
\left\lfloor \frac{x}{8} \right\rfloor - \left\lfloor \frac{x}{40} \right\rfloor + \left\lfloor \frac{x}{240} \right\rfloor = 210.
$$
(If $x$ is a real number, $\lfloor x \rfloor$ is the integer part of $x$, that is, the greatest integer less than or equal to $x$.)